目前分類：MATH (2)
- Dec 24 Wed 2008 20:55
有深度ㄉMATH問題2
- Dec 24 Wed 2008 20:42
有深度ㄉMATH問題
若t=x+1/x,則x4x3-4x2+x+1=0變成: {推甄}
(A)x2(t2+t-2)=0
(B)x2(t2+t-3)=0
(C)x2(t2+t-4)=0
(D)x2(t2+t-6)=0
若t=x+1/x,則x4x3-4x2+x+1=0變成: {推甄}
(A)x2(t2+t-2)=0
(B)x2(t2+t-3)=0
(C)x2(t2+t-4)=0
(D)x2(t2+t-6)=0
